book:chap2:2.11_problems
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book:chap2:2.11_problems [2021/11/12 16:27] – jv | book:chap2:2.11_problems [2022/04/01 21:30] (current) – jv | ||
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+ | [[forcestorques|2. Balancing Forces and Torques]] | ||
+ | * [[ 2.1 Motivation and Outline| 2.1 Motivation and outline: forces are vectors ]] | ||
+ | * [[ 2.2 Sets| 2.2 Sets ]] | ||
+ | * [[ 2.3 Groups| 2.3 Groups ]] | ||
+ | * [[ 2.4 Fields| 2.4 Fields ]] | ||
+ | * [[ 2.5 Vector spaces| 2.5 Vector spaces ]] | ||
+ | * [[ 2.6 Physics application balancing forces| 2.6. Physics application: | ||
+ | * [[ 2.7 The inner product | 2.7 The inner product]] | ||
+ | * [[ 2.8 Cartesian coordinates | 2.8 Cartesian coordinates]] | ||
+ | * [[ 2.9 Cross products --- torques| 2.9 Cross products — torques ]] | ||
+ | * [[ 2.10 Worked example Calder' | ||
+ | * ** 2.11 Problems ** | ||
+ | * [[ 2.12 Further reading| 2.12 Further reading ]] | ||
+ | |||
+ | ---- | ||
+ | |||
===== 2.11 Problems ===== | ===== 2.11 Problems ===== | ||
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<wrap # | <wrap # | ||
- | [[# | + | [[# |
The indicated angle from the downwards vertical to the ladder is denoted as $\theta$. | The indicated angle from the downwards vertical to the ladder is denoted as $\theta$. | ||
There is a gravitational force of magnitude $Mg$ acting of a ladder of mass $M$. | There is a gravitational force of magnitude $Mg$ acting of a ladder of mass $M$. | ||
- | At the point where it leans to the roof there is a normal force of magnitude | + | At the point where it leans to the wall there is a normal force $\mathbf N$ |
- | acting from the roof to the ladder. | + | acting from the wall to the ladder. |
- | At the ladder feet there is a normal force to the ground | + | At the ladder feet there is a normal force to the ground |
- | and a tangential friction force of magnitude $\gamma F_f$. | + | and a tangential friction force of magnitude $\gamma_1 f$. |
<WRAP 120pt left # | <WRAP 120pt left # | ||
- | {{10_Leaning_ladder_setup.png}} | + | {{: |
- | [[https:// | + | <wrap lo> |
- | Figure 2.27: Setup for [[# | + | [[https:// |
+ | Figure 2.27: Setup for [[# | ||
</ | </ | ||
- | - In principle there also is a friction force $\gamma_r | + | - In principle there also is a friction force $\gamma_2 |
- Determine the vertical and horizontal force balance for the ladder. Is there a unique solution? | - Determine the vertical and horizontal force balance for the ladder. Is there a unique solution? | ||
- | - The feet of the ladder start sliding when $F_f$ exceeds the maximum static friction force $\gamma F_g$. Which constraints do the force balance and this condition entail for the angles | + | - The feet of the ladder start sliding when $\gamma_1 f$ exceeds the maximum static friction force $\gamma_s f$. Which constraints do the force balance and this condition entail for the angles |
- Where does the mass of the ladder enter the discussion? Do you see why? | - Where does the mass of the ladder enter the discussion? Do you see why? | ||
- | - Determine the torque acting on the ladder. Does it matter whether you consider the torque with respect to the contact point to the roof, the center of mass, or the foot of the ladder? | + | - Determine the torque acting on the ladder. Does it matter whether you consider the torque with respect to the contact point to the wall, the center of mass, or the foot of the ladder? |
- | - Determine the threshold of sliding based on the balance of torques. \\ For metal feet on a wooden ground it takes a value of $\gamma \simeq 2$. For a slippery smooth ground it can be as small as $\gamma \simeq 0.3$. What does that tell about the range angles where the ladder starts to slide? | + | - Determine the threshold of sliding based on the balance of torques. \\ For metal feet on a wooden ground it takes a value of $\gamma_s |
- | - Why does a ladder commonly | + | - :!: Why does a ladder commonly |
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book/chap2/2.11_problems.1636730841.txt.gz · Last modified: 2021/11/12 16:27 by jv